AE 05: Joining fisheries

Suggested answers

Application exercise
Answers
library(tidyverse)
library(scales)

fisheries <- read_csv("data/fisheries.csv")
continents <- read_csv("data/continents.csv")

Working with multiple data frames

Often instead of being provided the data you need for your analysis in a single data frame, you will need to bring information from multiple datasets together into a data frame yourself. These datasets will be linked to each other via a column (usually an identifier, something that links the two datasets together) that you can use to join them together.

There are many possible types of joins. All have the format something_join(x, y).

x <- tibble(
  value = c(1, 2, 3),
  xcol = c("x1", "x2", "x3")
  )

y <- tibble(
  value = c(1, 2, 4),
  ycol = c("y1", "y2", "y4")
  )

x
# A tibble: 3 × 2
  value xcol 
  <dbl> <chr>
1     1 x1   
2     2 x2   
3     3 x3   
y
# A tibble: 3 × 2
  value ycol 
  <dbl> <chr>
1     1 y1   
2     2 y2   
3     4 y4

We will demonstrate each of the joins on these small, toy datasets.

inner_join(): join all rows from x where there are matching values in y 

Joining, by = "value"
# A tibble: 2 × 3
  value xcol  ycol 
  <dbl> <chr> <chr>
1     1 x1    y1   
2     2 x2    y2

left_join(): include all rows from x 

left_join(x, y)
Joining, by = "value"
# A tibble: 3 × 3
  value xcol  ycol 
  <dbl> <chr> <chr>
1     1 x1    y1   
2     2 x2    y2   
3     3 x3    <NA>

right_join(): include all rows from y 

Joining, by = "value"
# A tibble: 3 × 3
  value xcol  ycol 
  <dbl> <chr> <chr>
1     1 x1    y1   
2     2 x2    y2   
3     4 <NA>  y4

full_join(): include all rows in x or y (use this one sparingly!!)

full_join(x, y)
Joining, by = "value"
# A tibble: 4 × 3
  value xcol  ycol 
  <dbl> <chr> <chr>
1     1 x1    y1   
2     2 x2    y2   
3     3 x3    <NA> 
4     4 <NA>  y4

semi_join(): return all rows from x with match in y 

semi_join(x, y)
Joining, by = "value"
# A tibble: 2 × 2
  value xcol 
  <dbl> <chr>
1     1 x1   
2     2 x2

anti_join(): return all rows from x without a match in y 

anti_join(x, y)
Joining, by = "value"
# A tibble: 1 × 2
  value xcol 
  <dbl> <chr>
1     3 x3

Question: How do the join functions above know to join x and y by value? Hint: Examine the column names to find out.

[1] "value" "xcol" 
[1] "value" "ycol"

Global aquaculture production

The Fisheries and Aquaculture Department of the Food and Agriculture Organization of the United Nations collects data on fisheries production of countries.

Our goal is to create a visualization of the mean share of aquaculture by continent.

Let’s start by looking at the fisheries data frame.

glimpse(fisheries)
Rows: 82
Columns: 4
$ country     <chr> "Angola", "Argentina", "Australia", "Bangladesh", "Brazil"…
$ capture     <dbl> 486490, 755226, 174629, 1674770, 705000, 629950, 233190, 8…
$ aquaculture <dbl> 655, 3673, 96847, 2203554, 581230, 172500, 2315, 200765, 9…
$ total       <dbl> 487145, 758899, 271476, 3878324, 1286230, 802450, 235505, …

We have the countries, but our goal is to make a visualization by continent. Let’s take a look at the continents data frame.

glimpse(continents)
Rows: 245
Columns: 2
$ country   <chr> "Afghanistan", "Åland Islands", "Albania", "Algeria", "Ameri…
$ continent <chr> "Asia", "Europe", "Europe", "Africa", "Oceania", "Europe", "…
  • Your turn (2 minutes):
    • Which variable(s) will we use to join the fisheries and continents data frames?
    • We want to keep all rows and columns from fisheries and add a column for corresponding continents. Which join function should we use?
  • Demo: Join the two data frames and name assign the joined data frame back to fisheries.
fisheries <- fisheries |>
  left_join(continents)
Joining, by = "country"
  • Demo: Take a look at the updated fisheries data frame. There are some countries that were not in continents. First, identify which countries these are (they will have NA values for continent). Then, manually update the continent information for these countries using the case_when function. Finally, check that these updates have been made as intended and no countries are left without continent information.
fisheries |>
  filter(is.na(continent))
# A tibble: 3 × 5
  country                          capture aquaculture   total continent
  <chr>                              <dbl>       <dbl>   <dbl> <chr>    
1 Democratic Republic of the Congo  237372        3161  240533 <NA>     
2 Hong Kong                         142775        4258  147033 <NA>     
3 Myanmar                          2072390     1017644 3090034 <NA>     
fisheries <- fisheries %>%
  mutate(
    continent = case_when(
      country == "Democratic Republic of the Congo" ~ "Africa",
      country == "Hong Kong" ~ "Asia",
      country == "Myanmar" ~ "Asia",
      TRUE ~ continent
    )
  )

fisheries |>
  filter(is.na(continent))
# A tibble: 0 × 5
# … with 5 variables: country <chr>, capture <dbl>, aquaculture <dbl>,
#   total <dbl>, continent <chr>
  • Demo: Add a new column to the fisheries data frame called aq_prop. We will calculate it as aquaculture / total. Save the resulting frame as fisheries.
fisheries <- fisheries |>
  mutate(aq_prop = aquaculture / total)
  • Your turn (5 minutes): Now expand your calculations to also calculate the mean, minimum and maximum aquaculture proportion for continents in the fisheries data. Note that the functions for calculating minimum and maximum in R are min() and max() respectively.
fisheries |>                              # start with fisheries data frame
  group_by(continent) |>                  # group by continent
  summarize(                              # calculate summary stats  
    min_aq_prop  = min(aq_prop),
    mean_aq_prop = mean(aq_prop),
    max_aq_prop  = max(aq_prop)
    )    
# A tibble: 5 × 4
  continent min_aq_prop mean_aq_prop max_aq_prop
  <chr>           <dbl>        <dbl>       <dbl>
1 Africa        0             0.0943       0.803
2 Americas      0             0.192        0.529
3 Asia          0             0.367        0.782
4 Europe        0.00682       0.165        0.618
5 Oceania       0.0197        0.150        0.357
  • Demo: Create a new data frame called fisheries_summary that calculates minimum, mean, and maximum aquaculture proportion for each continent in the fisheries data.
fisheries_summary <- fisheries |>         # start with fisheries data frame
  group_by(continent) |>                  # group by continent
  summarize(                              # calculate summary stats  
    min_aq_prop  = min(aq_prop),
    mean_aq_prop = mean(aq_prop),
    max_aq_prop  = max(aq_prop)
    )
  • Demo: Then, determine which continent has the largest value of max_ap. Take the fisheries_summary data frame and order the results in descending order of mean aquaculture proportion.
fisheries_summary |>            # start with fisheries_summary data frame
  arrange(desc(mean_aq_prop))   # order in descending order of mean_aq_prop
# A tibble: 5 × 4
  continent min_aq_prop mean_aq_prop max_aq_prop
  <chr>           <dbl>        <dbl>       <dbl>
1 Asia          0             0.367        0.782
2 Americas      0             0.192        0.529
3 Europe        0.00682       0.165        0.618
4 Oceania       0.0197        0.150        0.357
5 Africa        0             0.0943       0.803
  • Demo: Recreate the following plot using the data frame you have developed so far.

ggplot(fisheries_summary, 
       aes(y = fct_reorder(continent, mean_aq_prop), x = mean_aq_prop)) +
  geom_col() +
  scale_x_continuous(labels = label_percent(accuracy = 1)) +
  labs(
    x = NULL,
    y = NULL,
    title = "Average share of aquaculture by continent",
    subtitle = "out of total fisheries harvest, 2016",
    caption = "Source: bit.ly/2VrawTt"
  ) +
  theme_minimal()

  • Your turn (optional): Change the theme of the plot and make any other changes you would like to improve it.
# add your code here